Molecular Spectra

10.2 Molecular Spectra
Learning Objectives
- Use the concepts of vibrational and rotational energy to describe energy transitions in a diatomic molecule
- Explain key features of a vibrational-rotational energy spectrum of a diatomic molecule
- Estimate allowed energies of a rotating molecule
- Determine the equilibrium separation distance between atoms in a diatomic molecule from the vibrational-rotational absorption spectrum
Energy of a Molecule
Rotational Energy

Practice!
| Practice 10.2.1 |
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| A gas of identical diatomic molecules absorbs electromagnetic radiation over a wide range of frequencies. Molecule 1 is in the ℓ = 0 rotation state and makes a transition to the ℓ = 1 state. Molecule 2 is in the ℓ = 2 state and makes a transition to the ℓ = 3 state. The ratio of the frequency of the photon that excited molecule 2 to that of the photon that excited molecule 1 is equal to: |
| A. 1 |
| B. 2 |
| C. 3 |
| D. 4 |
| E. impossible to determine |
| Practice 10.2.2 |
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| The moment of inertia of a CO molecule is 1.46 x 10–46 kg · m2. What is the wavelength of the photon emitted if a rotational transition occurs from the ℓ = 3 to the ℓ = 2 state? |
| A. 430 µm |
| B. 870 µm |
| C. 1740 µm |
| D. 550 µm |
| E. 290 µm |
| Practice 10.2.3 |
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| A molecule makes a transition from the ℓ = 1 to the ℓ = 0 rotational energy state. The wavelength of the emitted photon is 2.6 x 10–3 m. What is the moment of inertia of the molecule? |
| A. 2.9 x 10–46 kg·m2 |
| B. 5.7 x 10–45 kg·m2 |
| C. 1.1 x 10–44 kg·m2 |
| D. 1.5 x 10–46 kg·m2 |
| E. 9.1 x 10–46 kg·m2 |
| Practice 10.2.4 |
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| An oxygen molecule has a moment of inertia of 5 x 10–46 kg·m2. Calculate the bond length. Recall that the atomic mass of oxygen is 16 u (1 u = 1.66 x 10–27 kg). |
| A. 0.3 nm |
| B. 0.1 nm |
| C. 0.2 nm |
| D. 0.4 nm |
| E. 0.5 nm |

Discuss!
Calculate the energies and wavelengths of the three lowest rotational radiations emitted by molecular H2. For H2, the reduced mass is equal to half the mass of a hydrogen atom and r0 = 0.074 nm.
Vibrational Energy

Practice!
| Practice 10.2.5 |
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| Which is easier to excite in a diatomic molecule, rotational or vibrational motion? |
| A. rotational motion |
| B. vibrational motion |
| C. both the same |
| Practice 10.2.6 |
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| The fundamental frequency of the diatomic molecule CO is 6.42 x 1013 Hz. If the atomic masses are 12 u and 16 u (1 u = 1.66 x 10–27 kg), find the force constant for the diatomic molecule. |
| A. 970 N/m |
| B. 1530 N/m |
| C. 1850 N/m |
| D. 480 N/m |
| E. 47 N/m |
| Practice 10.2.7 |
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| The fundamental frequency of the diatomic molecule HF is 8.72 x 1013 Hz. The energy associated with a transition from the 10th to the 9th vibrational quantum number (in eV) is |
| A. 3.6 eV |
| B. 0.36 eV |
| C. 0.06 eV |
| D. 0.6 eV |
| E. 0.18 eV |
Molecular Spectroscopy

Practice!
| Practice 10.2.8 |
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| The energy levels of a diatomic molecule are denoted by a vibrational quantum number n and a rotational quantum number ℓ. Transitions from one level to a lower level involves the emission of a photon. Which of the following transitions are allowed? |
| A. n = 2, ℓ = 1 to n = 1, ℓ = 0 |
| B. n = 3, ℓ = 1 to n = 2, ℓ = 2 |
| C. n = 4, ℓ = 2 to n = 3, ℓ = 0 |
| D. Both A and B are allowed. |
| E. All three of A, B, and C are allowed. |
| Practice 10.2.9 |
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![]() This diagram shows the vibrational and rotational energy levels of a diatomic molecule. Consider two possible transitions for this molecule: I. n = 2, ℓ = 5 to n = 1, ℓ = 4 II. n = 2, ℓ = 1 to n = 1, ℓ = 0 The energy change of the molecule is |
| A. greater for transition I. |
| B. greater for transition II. |
| C. the same for both transitions. |
